Let $f\left(x\right)$ and $g\left(x\right)$ be two real polynomials of degree 2 and 1 respectively .If $f\left(g\left(x\right)\right)=8x^2-2x$ and $g\left(f\left(x\right)\right)=4x^2+6x+1$ then the value of $f\left(2\right)+g\left(2\right)=\_\_\_\_\_$

$\begin{array}{l}f\left(x\right)=a{x}^2+bx+c,g\left(x\right)=px+q\\ f\left(g\left(x\right)\right)=8x^2-2x,g\left(f\left(x\right)\right)=4x^2+6x+1\\ \Rightarrow a{(px+q)}^2+b(px+q)+c=8x^2-2x\\ a{p}^2=8,2apq+bp=-2,a{q}^2+bq+c=0\\ andp(a{x}^2+bx+c)+q=4x^2+6x+1\\ \Rightarrow ap=4,bp=6,cp+q=1\\ a{p}^2=8andap=4\Rightarrow p=2,a=2b=3\\ c=1,q=-1\\ \therefore f\left(x\right)=2x^2+3x+1,g\left(x\right)=2x-1\\ f\left(2\right)+g\left(2\right)=15+3=18\end{array}$