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Q.

Let f(x) be a function for all xR and f(0)=1. Then g(x)=f(|x|)1cos2x2, at x=0,

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a

is non- differentiable at x = 0 as its graph has vertical tangent at x = 0

b

is differentiable at x = 0 and its value is 0

c

is differentible at x = 0 and its value is 1

d

is non- differentiable at x = 0 as its graph has sharp turn at x = 0

answer is B.

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Detailed Solution

g(0+)=limh0f(h)|sinh|f(0)+h

limh0f(h)f(0)hlimh0sinhh=11=0

g(0)=limh0f(|h|)|sin(h)|f(0)h

limh0f(h)f(0)h+limh0sinhh=1+1=0

Thus,g(x)is differentiable andg(0)=0

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