Q.

 Let f(x) be a function, satisfying f:[0,1], and 501(f(x))2dx+1=1001x2f(x)dx then which is/are correct 

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a

f12=14

b

f(x)=ex has unique solution 

c

 Maximum value of f(x) is equal to '1 

d

f(x) is concave down everywhere in (0,1)

answer is A, C.

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Detailed Solution

Given 501fx2dx+1=1001x2fxdx 501fx2dx+501x4dx=1001x2fxdx501fx22x2fx+x22dx=0501fxx22dx=0fx=x2f12=14The function has maximum value 1  in the given interval

 

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