Let f(x)=sin2nx1+cos2nx ; n∈N has π6 as fundamental period, then n is equal to

f(x)=sin2nx1+cos2nx =sin2nx1+1+cos2nx2 period is 2π2n=π6⇒n=6

Let f(x)=sin2nx1+cos2nx ; n∈N has π6 as fundamental period, then n is equal to

f(x)=sin2nx1+cos2nx =sin2nx1+1+cos2nx2 period is 2π2n=π6⇒n=6

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Let $f (x) = \frac{\sin 2 n x}{1 + \cos^{2} n x}; n \in N$ has $\frac{π}{6}$ as fundamental period, then n is equal to

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Detailed Solution

$f (x) = \frac{\sin 2 n x}{1 + \cos^{2} n x} = \frac{\sin 2 n x}{1 + \frac{1 + \cos 2 n x}{2}} p e r i o d i s \frac{2 π}{2 n} = \frac{π}{6} \Rightarrow n = 6$

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