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Q.

Letfx=sin2x2+cos2xcos2x2+sin2xcos2xcos2xsin2xcos2x1+cos2x,x0,π. Then the maximum value of fx is equal to _______

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answer is 6.

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Detailed Solution

Applying R1R1R2,   R2R2R3

fx=220201sin2xcos2x1+cos2x=4+2cos2x

Max.value =4+2=6

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