Let $f\left(x\right) = \left\{\begin{array}{ll}\frac{\sin (x - \left[x\right])}{x - \left[x\right]}& , x \in (-2,-1)\\ max\{2x, 3\left[\left|x\right|\right]\}& , \left|x\right| < 1\\ 1& , otherwise\end{array}\right.$

where [t] denotes greatest integer ≤ t. If m is the number of points where f is not continuous and n is the number of points where f is not differentiable, then the ordered pair (m,n) is:

$f\left(x\right)=\left\{\begin{array}{cl}\frac{\sin (x+2)}{x+2}& ,x\in (-2,-1)\\ max\{2x,0\}& ,x\in (-1,1)\\ 1& ,\text{ otherwise }\end{array}\right.$

$$\begin{gathered} f\left(-2^{+}\right)=\underset{h\to 0}{lim} f(-2+h)=\underset{h\to 0}{lim} \frac{\sinh }{h}=1 \\ \mathrm{f} \mathrm{is} \mathrm{continuous} \mathrm{at} \mathrm{x}=-2 \\ \begin{array}{r}f\left(-1^{-}\right)=\underset{\mathrm{h}\to 0}{lim} \frac{\sin (-1-\mathrm{h}+2)}{(-1-h+2)}=\sin 1\\ f(-1)=f\left(-1^{+}\right)=0\end{array} \\ f\left(1^{+}\right)=1\mathrm{\&}f\left(1^{-}\right)=0\Rightarrow f\text{ is not continuous at }x=1 \\ f\text{ is continuous but not diff. at }\mathrm{x}=0 \\ \left.\begin{array}{l}\Rightarrow \mathrm{f}\text{ is discontinuous at }\mathrm{x}=-1\mathrm{\&}1\\ \mathrm{\&}\mathrm{f}\text{ is not diff. at }\mathrm{x}=-1,0\mathrm{\&}1\end{array}\right\}\Rightarrow \begin{array}{r}\mathrm{m}=2\\ \mathrm{n}=3\end{array} \end{gathered}$$