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Q.

Letf(x)=sinx+cosx,  g(x)=x21.Theng(f(x))isinvertibleforx

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a

[π2,  0]

b

[π2,π]

c

[π4,π4]

d

[0,  π2]

answer is C.

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Detailed Solution

f(x)=sinx+cosx,   g(x)=x21g(f(x))=g(sinx+cosx)   =  (sinx+cosx)21  =sin2x+cos2x+2sinxcosx1  =1+2sinxcosx1  =sin2xWe  know  that  1sin2x1  2x[π2,  π2]x[π4,   π4]

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