Let $\mathrm{f}\left(\mathrm{x}\right)={\mathrm{x}}^2-4\mathrm{x}-3,\mathrm{x}>2\text{ and }\mathrm{g}\left(\mathrm{x}\right)$ be the inverse of f(x). Then the value of$\frac{1}{{\mathrm{g}}^{\mathrm{\prime }}\left(2\right)}$is (here g' represents the first derivative of g)