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Q.

Let fx=x3+x216x+20x22kIf  x2    ifx=2, If f(x) is continuous for all x then k =

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a

11

b

7

c

15

 

d

5

answer is B.

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Detailed Solution

k=f(2)=Ltx2  f(x)=Ltx2x3+x216x+20(x2)2=Ltx23x2+2x162(x2)=Ltx26x+22=7

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