Let $n_1$and $n_2$ be the number of red and black balls respectively, in box I. Let $n_3$ and $n_4$  be the number of red and black balls, respectively, in box II.

One of the two boxes, box I and box II, was selected at random and a ball was drawn randomly out of this box. The ball was found to be red. If the probability that red ball was drawn from box II is $\frac{1}{3},$ then the correct option (s) with the possible values of  $n_1,n_2,n_3$and  $n_4$ is (are)