Let ${\mathrm{n}}_{\mathrm{p}}$ and ${\mathrm{n}}_{\mathrm{e}}$ be the numbers of holes and conduction electrons in an intrinsic semiconductor. 
 

• Since there is no doping in intrinsic material, the number of carriers for holes and electrons in an intrinsic semiconductor is equal.
• .equal no of holes electrons are created due to breaking of covalent  bond
  So,${\mathrm{n}}_{\mathrm{p}}={\mathrm{n}}_{\mathrm{e}}$.

Hence the correct answer is ${\mathrm{n}}_{\mathrm{p}}={\mathrm{n}}_{\mathrm{e}}.$