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Let $O (0, 0), P (3, 4)$ and $Q (6, 0)$ be the vertices of triangle OPQ. The point R inside the triangle OPQ is such that the triangles OPR, PQR, OQR are of equal area. The coordinates of R is

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$(3, \frac{2}{3})$

$(3, \frac{4}{3})$

$(\frac{4}{3}, 3)$

$(\frac{4}{3}, \frac{2}{3})$

answer is B.

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Detailed Solution

R should be centroid of $Δ O P Q$

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