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Q.

Let P1:x+y+z=0,P2:x+y+2z=1,P3:ax+by+3z=1,P1,P2&P3 have infinite point of intersection then value of a+b such that distance of P3 from x1=y12=z13 is maximum is
 

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a

3

b

-3

c

6

d

-6

answer is D.

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Detailed Solution

DR of normal vector of P3 should be 1,1,1 so a=b=3

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