Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Let p,q and (13 i)200=2199(p+iq),i=1 Then p + q + q2 and p - q + q2 are roots of the equation.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

x2 + 4x + 1 = 0

b

x2 - 4x - 1 = 0

c

x2 + 4x - 1 = 0

d

x2 - 4x + 1 = 0

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

detailed_solution_thumbnail

(1+3i)200=2199(p+iq)220012+i.32200=2199(p+iq) 2ω2200=p+iq2ω=p+iqp=1,q=3
α=p+q+q2=23β=pq+q2=2+3α+β=4αβ=1

Required equation is x2 - 4x + 1 = 0

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring