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Q.

Let r be a unit vector satisfying  r×a=b, where |a|=3 and |b|=2 then

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a

r=23(aa×b)

b

r=13(a+a×b)

c

r=13(a+a×b)

d

r=23(a+a×b)

answer is B, D.

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Detailed Solution

a×(r×a)=a×b 3r(ar)a=a×b Also  |r×a|=|b| sin2θ=23 or  1cos2θ=23 or  13=cos2θ ar=±1 3r±a=a×b or  r=13(a×b±a)

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