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Q.

Let V1 be the potential at the centre of the square of side 1m when the charges at the four corners are 2C each. If the same charges are placed at the corners of a square of side 2m, then the potential at the centre of this square is V2. The value of V2V1 is

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a

12

b

142

c

122

d

12

answer is A.

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Detailed Solution

Vcentre1=K×212×4=V1

Vcentre2=K×222×4=V2

So, V2V1=12

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