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Q.

Let $x < 1,$ then the value of $|\begin{array}{l} x^{2} + 2 2 x + 1 1 \\ 2 x + 1 x + 2 1 \\ 3 31 \end{array}|$ is

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a

Negative

b

Non-negative

c

Non-positive

d

Positive

answer is C.

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Detailed Solution

Apply $R_{1} \to R_{1} - R_{2}$

and $R_{2} \to R_{2} - R_{3}$ and expand

then we get

given determinant= ${(x - 1)}^{2} (x - 3)$

$\sin c e x < 1 t h e n g i v e n d e t e r m i n a n t i s n e g a t i v e$

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Let x<1,then the value of x2+2 2x+1 12x+1 x+2 13 3 1 is