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Q.

Let x1x2x3x4x5x4x3x2x1be a nine digit palindrome such that either the sequence x1, x2, x3, x4, x5  is a strictly ascending or strictly descending. Then the number of such palindromes is

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a

9×9P4

b

3×9P5

c

9C5

d

3×9C5

answer is D.

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Detailed Solution

Strictly descending C5   10
Strictly ascending C5   9(because zero can’t be at x1)
 10C5+9C5=29C4+9C4=39C4=39C5

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