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Q.

Let ⨍ (x)=5-x-2 and g(x)=x+1, xR. If ⨍ (x) attains maximum value at α and g(x) attains minimum value at β, then limxαβ(x-1)(x2-5x+6)x2-6x+8 is equal to

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a

–3/2

b

3/2

c

1/2

d

–1/2

answer is B.

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Detailed Solution

x-20 f(x)=5-x-2 is max at x=2=α g(x)=x+10 g(x) is min at x=-1=β limx2 (x-1)(x-2)(x-3)(x-2)(x-4)=(1)(-1)(-2)=12

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