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Let ${⨍ (x)=∫e}^{x} (x-1)(x-2)dx.$
Then $⨍$ decreases in the interval

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(1, 2)

$(- \infty, - 2)$

(–2, –1)

$(2, \infty)$

answer is C.

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Detailed Solution

$⨍^{1} {(x)=e}^{x} (x-1) (x-2)$

$⨍ (x)$ is decreases

$⨍^{1} (x)<0$

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$x \in (1, 2)$

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