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lf a + b + c=0, then the roots of the equation 4ax2+3bx+2c=0 are

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a
equal
b
imaginary
c
real
d
None of these

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detailed solution

Correct option is C

 Given, a, + b + c=0 ………………..(i)
and 4ax2+3bx+2c=0
D=b24acD=(3b)24(4a)(2c)=9b232ac
=9(a+c)232ac [ from Eq. (i) ]=9(ac)2+4ac>0
Hence, roots are real. 

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