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Q.

lf the equation of the plane passing through thr point 2,-1, 3 and perpendular to 3x-2y+z=9, x+y+z=9 is x+by+cz+d=0 then d =

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a

11/3

b

0

c

3

d

1/3

answer is A.

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Detailed Solution

x-2y+1z-33-21111=0(x-2) (-3)-(y+1) (2)+(z-3) (5)=0-3x+6-2y-2+5z-15=03x+2y-5z+11=0x+23y-53z+113=0b=23  c=-53  d=113

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