Q.

lf y = mx+ c be a tangent to hyperbola x2λ2y2λ3+λ2+λ2=1 then least value of 16m2 equal to

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a

0

b

4

c

9

d

1

answer is C.

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Detailed Solution

c2=a2m2b2c2=λ2m2λ3+λ2+λ2c20m2λ2+λ+12λ2+λ+1 has minimum value 34m2916

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lf y = mx+ c be a tangent to hyperbola x2λ2−y2λ3+λ2+λ2=1 then least value of 16m2 equal to