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Q.

lf a,b,c  are  unit vectors such that  a.b=a.c=0 and b,c π6, then a=

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a

±a×c

b

±2a×c

c

±b×c

d

±2b×c

answer is D.

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Detailed Solution

|a|=|b|=|c|=1a·b-a·c=0    a·(b-c)=0(or)  ab  and  ac    a || b×c  a=λ (b×c)|a|=|λ|  |b×c|    1=|λ| (1×1×sin π6)  λ=±2    a=±2(b×c)

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