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Q.

lf x=2ω-1 then x4+5x3+9x2-x-14==

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a

0

b

14

c

-14

d

28

answer is A.

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Detailed Solution

x=2ω-1x2=4ω2-4ω+1

x3=4ω2-4ω+12ω-1=8-4ω2-8ω2+4ω+2ω-1=7-12ω2+6ω

x4=7-12ω2+6ω2ω-1 =14ω-7-24+12ω2+12ω2-6ω=24ω2+8ω-31

x4+5x3+9x2-x-14= 24ω2+8ω-31+57-12ω2+6ω+94ω2-4ω+1-2ω-1-14 =0

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