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Q.

lf xn=ωn+1ωn then x1x2x3...........x12=

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a

8

b

16

c

32

d

4

answer is C.

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Detailed Solution

xn=wn+1wnx1=w+1w=w+w2=-1,  x2=w2+1w2=w2+w=-1x3=w3+1w3=2x1x2x3.....x12=x1x2x34=(-1) (-1) (2)4 =16

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