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Q.

lf ω =z2-1,where ω is a cube root of unity  and z=x+iy then  12Tan-1yx+1+Tan-1yx-1=

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a

π2

b

π6

c

π3

d

π4

answer is B.

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Detailed Solution

w=z2-1,  z=x+iy    w2=(x+iy)2-1     

  -1-i32  =x2-y2-1+i2xy

 x2-y2-1=-12and   2  xy =   -32

12tan-1yx+1+tan-1yx-1

12tan-1yx+1+yx-11-yx+1·yx-1

=12tan-12xyx2-y2-1

=12 tan-1 -32-12

=12tan-13=12π3=π6

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