Light beam is described by $E = 800 sinω (t - \frac{x}{c}) .$ An electron is allowed to move normal to the propagation of light beam with a speed of $3 \times 10^{7} m / s .$ What is the maximum magnetic force exerted on the electron.

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$12.8 \times 10^{- 17} N$

$12.8 \times 10^{- 18} N$

$1.28 \times 10^{- 21} N$

$1.28 \times 10^{- 18} N$

answer is C.

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Detailed Solution

$E_{0} = 800 V / m$

$B_{0} = \frac{E_{0}}{C} = \frac{800}{3 \times 10^{8}} T$

$F_{m} = {qνB}_{0} = \frac{1.6 \times 10^{- 19} \times 3 \times 10^{7} \times 800}{3 \times 10^{8}}$

$= 12.8 \times 10^{- 18} newton .$

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