Q.

Light from a monochromatic point source S is incident on the two slits of an opaque wall placed at a distance L as shown in the diagram, Intensity of interference pattern is observed at the point P on the screen placed at a distance L behind the slits. When the upper slit is shifted upward then the distance between the slits is changed from  200 μm  to  400 μm,  the intensity at P changes from  Imax to  34Imax. If L=1 m, then find the wave length of light used  (inA)

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answer is 4800.

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Detailed Solution

34|max=|maxcos2ϕ2cosϕ2=32 ϕ2=π6ϕ=π/3 ϕ=2πλΔx=π3Δx=λ6 Given    d=200μm=2×104m

2[L2+9d24L2+d24]=λ6 2d2L=λ6          λ=12d2L=12×4×1081=4800A

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