Light of wavelength $λ$ strikes a photo electric surface and electrons are ejected with maximum kinetic energy K. If K is to be increased to twice its original value, the wavelength must be changed to $λ^{'} .$ $I f λ = 6200 \overset{o}{A} a n d λ^{'} = 5000 \overset{o}{A},$ Then value of k is

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1.26 eV

0.86 eV

0.48 eV

1.62 eV

answer is C.

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Detailed Solution

(3)

$\begin{array}{l} \frac{h c}{λ} = ϕ + k .... (1) a n d \frac{h c}{λ^{'}} = ϕ + 2 k .... (2) \\ (2) - (1), k = \frac{h c}{λ^{'}} - \frac{h c}{λ} = (\frac{12400}{5000} - \frac{12400}{6200}) \overset{o}{A} = 0.48 e V \end{array}$

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