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Light of wavelength 5000 $\overset{0}{A}$ falls on a sensitive plate with photo electric work function 1.9 eV. The kinetic energy of the photo electrons emitted will be

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0.58 eV

2.48 eV

1.24 eV

1.16 eV

answer is A.

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Detailed Solution

$K{E_{max }} = E - {W_0} = frac{{hc}}{lambda } - {W_o}$

$= frac{{12400eV{mathop Alimits^0 }}}{{5000{mathop Alimits^0 }}} - 1.9eV = 0.58eV$

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