Q.

Light of wavelength 6000A0 is incident on a single slit. The first minimum of the diffraction pattern is obtained at 4 mm from the center. The screen is at a distance of 2m from the slit. The slit width will be 

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a

0.15 mm

b

0.3 mm

c

0.2 mm

d

0.1 mm

answer is A.

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Detailed Solution

Minimum condition for diffraction is 
dYD=,d4×1032=1×6000×1010d=3×104m=0.3mm

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