Light of wavelength 6000A⁰ is incident on a single slit. The first minimum of the diffraction pattern is obtained at 4 mm from the center. The screen is at a distance of 2m from the slit. The slit width will be

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0.15 mm

0.3 mm

0.2 mm

0.1 mm

answer is A.

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Detailed Solution

Minimum condition for diffraction is
$\begin{array}{l} d \frac{Y}{D} = nλ, d \frac{4 \times 10^{- 3}}{2} = 1 \times 6000 \times 10^{- 10} \\ d = 3 \times 10^{- 4} m = 0 .3 mm \end{array}$

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