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Light of wavelength $2000 Å$ is incident on a metal surface of work-function $3.0 e V$ . Find the minimum and maximum kinetic energy of the photoelectrons.

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0, $3.19 e V$

3.0 eV, $4.19 e V$

0, $5.19 e v$

3 eV, $6.19 e V$

answer is A.

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Detailed Solution

$K_{m i n} = 0$
and $K_{m a x} = E - W = \frac{12375}{2000} - 3.0 \approx 3.19 e V$

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