Light passes symmetrically through an equilateral prism. After emergence, it is incident on a plane mirror fixed to the base of the prism extending beyond it. Find the deviation produced. ( $μ$ of the prism material is $\sqrt{2}$ ).

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Detailed Solution

A = r₁ + r₂ ; under minimum deviation r₁ = r₂ = A/2 = 30º

$μ = \frac{{Sini}_{2}}{{Sinr}_{2}} \Rightarrow i_{2} = 45^{\circ} \Rightarrow θ = 75^{\circ}$

$μ = \frac{Sin (\frac{A + D}{2})}{Sin A / 2}$

deviation by prism, $D_{1} = 30^{\circ} (CW)$

deviation by mirror:
$D_{2} = 180^{\circ} - 2 θ = 30^{\circ} (ACW)$ ;

net deviation: $D = 30^{\circ} - 30^{\circ} = 0^{\circ}$

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