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Q.

Light passes through a glass plate of thickness d and refractive index $μ$ . For small angles of incidence ( $θ$ ), the lateral displacement is :

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a

$\frac{dθμ}{(μ - 1)}$

b

d $θ$

c

$dθ (\frac{μ - 1}{μ})$

d

$dθ (μ - 1)$

answer is D.

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Detailed Solution

$μ = \frac{sinθ}{sinr} = \frac{θ}{r}$ (small angles)
Lateral displacement $= \frac{dsin (θ - r)}{cosr}$
$= d (θ - r)$

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