Light ray is travelling from a denser medium into a rarer medium. The velocity of light in the denser medium is 2×108m/sec. and in the rarer medium is 2.5×108m/sec The critical angle of the two media is

sinC=VdVr=μrμd⇒C=sin-12×1082.5×108=sin-145

Light ray is travelling from a denser medium into a rarer medium. The velocity of light in the denser medium is 2×108m/sec. and in the rarer medium is 2.5×108m/sec The critical angle of the two media is

sinC=VdVr=μrμd⇒C=sin-12×1082.5×108=sin-145

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Light ray is travelling from a denser medium into a rarer medium. The velocity of light in the denser medium is $2 \times 10^{8} m / \sec .$ and in the rarer medium is $2.5 \times 10^{8} m / \sec$ The critical angle of the two media is

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$\sin^{- 1} (\frac{5}{4})$

$\sin^{- 1} (\frac{1}{2})$

$\sin^{- 1} (\frac{3}{5})$

$\sin^{- 1} (\frac{4}{5})$

answer is B.

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Detailed Solution

$sinC = \frac{V_{d}}{V_{r}} = \frac{μ_{r}}{μ_{d}}$

$\Rightarrow C = \sin^{- 1} (\frac{2 \times 10^{8}}{2.5 \times 10^{8}}) = \sin^{- 1} (\frac{4}{5})$

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Light ray is travelling from a denser medium into a rarer medium. The velocity of light in the denser medium is 2×108m/sec. and in the rarer medium is 2.5×108m/sec The critical angle of the two media is

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Light ray is travelling from a denser medium into a rarer medium. The velocity of light in the denser medium is $2 \times 10^{8} m / \sec .$ and in the rarer medium is $2.5 \times 10^{8} m / \sec$ The critical angle of the two media is