Light takes time t1 to travel a distance x1 in vacuum and the same light takes time t2 to travel a distance x2 in a medium. The critical angle for the medium is

C=Sin−1⁡μ1μ2=Sin−1⁡V2V1=Sin−1⁡x2+1x1+2

Light takes time t1 to travel a distance x1 in vacuum and the same light takes time t2 to travel a distance x2 in a medium. The critical angle for the medium is

C=Sin−1⁡μ1μ2=Sin−1⁡V2V1=Sin−1⁡x2+1x1+2

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Light takes time t₁ to travel a distance x₁ in vacuum and the same light takes time t₂ to travel a distance x₂ in a medium. The critical angle for the medium is

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$\sin^{- 1} (\frac{x_{2} t_{2}}{x_{1} t_{1}})$

$\sin^{- 1} (\frac{x_{1} t_{2}}{x_{2} t_{1}})$

$\sin^{- 1} (\frac{x_{1} t_{1}}{x_{2} t_{2}})$

$\sin^{- 1} (\frac{x_{2} t_{1}}{x_{1} t_{2}})$

answer is D.

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$C = {Sin}^{- 1} (\frac{μ_{1}}{μ_{2}}) = {Sin}^{- 1} (\frac{V_{2}}{V_{1}}) = {Sin}^{- 1} (\frac{x_{2} + 1}{x_{1} + 2})$

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Light takes time t1 to travel a distance x1 in vacuum and the same light takes time t2 to travel a distance x2 in a medium. The critical angle for the medium is

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Light takes time t₁ to travel a distance x₁ in vacuum and the same light takes time t₂ to travel a distance x₂ in a medium. The critical angle for the medium is