Light wave traveling in air along x-direction is given by $E_{y} = 540 \sin π \times 10^{4} (x - ct) {Vm}^{- 1}$ . Then, the peak value of magnetic field of wave will be $(Given c = 3 \times 10^{8} {ms}^{- 1})$

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$54 \times 10^{- 8} T$

$18 \times 10^{- 7} T$

$54 \times 10^{- 7} T$

$18 \times 10^{- 8} T$

answer is A.

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Detailed Solution

$\begin{array}{l} E_{y} = 540 \sin π \times 10^{4} (x - ct) {Vm}^{- 1} \\ E_{0} = 540 {Vm}^{- 1} \\ B_{0} = \frac{E_{0}}{C} = \frac{540}{3 \times 10^{8}} = 18 \times 10^{- 7} T \end{array}$

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