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Light with an energy flux of 18 Wcm^-2 falls on perfect absorbing surface normally. If the surface area is 20 cm², then average force during 30 minute span is

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1.2×10^-6N

2.4×10^-6N

3.6×10^-7N

4.48×10^-6N

answer is A.

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Detailed Solution

$U = (18 W / {cm}^{2}) \times (20 {cm}^{2}) \times (30 \times 60) = 6.48 \times 10^{5} J$

$p = \frac{U}{c} = \frac{6.48 \times 10^{5} J}{3 \times 10^{8} m / s} = 2.16 \times 10^{- 3} kgm / s$

$F = \frac{p}{t} = \frac{2.16 \times 10^{- 3}}{0.18 \times 10^{4}} = 1.2 \times 10^{- 6} N$

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