Light with energy flux of 24 Wm^–2 is incident on a well polished disc of radius 3.5 cm for one hour. The momentum transferred to the disc is

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3.3 $μ$ kg ms^-1

4.4 $μ$ kg ms^-1

1.1 $μ$ kg ms^-1

2.2 $μ$ kg ms^-1

answer is B.

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Detailed Solution

Total energy incident

U = flux × Area × time

$\begin{array}{rcl} = & 24 x π {(3.5 x 10^{- 2})}^{2} x 60 x 60 \\ = & 332.34 \\ p & = & \frac{2 U}{C} \\ = & \frac{2 x 332.34}{3 x 10^{8}} \\ = & 2.2 x 10^{- 6} kg {ms}^{- 1} \\ = & 2.2 μ kg {ms}^{- 1} \end{array}$

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