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Q.

Limiting molar conductivities for NaCl, HCl and NaAC are 126.4, 425.9 and 91.0 SCm2  mol−1 respectively. Limiting molar conductivity for HAC in Scm2mol−1 is

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a

461.3

b

390.5

c

293.3 

d

643.3

answer is A.

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Detailed Solution

Λºm(HAC)=Λºm(HCl)+Λºm(NaAC)
−Λºm(NaCl) =425.9+91−126.4
=390.5   Scm2mol−1

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