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Q.

limnr=2n(r3+1r31)=

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a

2

b

1

c

12

d

32

answer is C.

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Detailed Solution

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limnr=2n(r+1r1)r=2n(r2r+1r2+r+1)

=Ltn31·42·53····n+1n1·37·713····n2n+1n2+n+1

=Ltn11·2n(n+1)3n2+n+1

=Ltn321+1n1+1n+1n2=32

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limn→∞∏r=2n(r3+1r3−1)=