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Q.

limt0(11 sin2t+21 sin2t+...............+n1 sin2t) sin2t is equal to 

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a

n

b

n2n

c

n2

d

n(n+1)2

answer is A.

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Detailed Solution

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ltt0(1cosec2t+2cosec 2t+.....+ncosec2t)sin2t

ltt0    n[(1n)cosec2t+(2n)cosec2t+.......+1]sin2t=n(0+0+.....+1)=n

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