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Q.

limx1  nxn+1-n+1xn+1ex-esinπx  where n=100, is equal to

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a

5050πe

b

100πe

c

-5050πe

d

-4950πe

answer is C.

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Detailed Solution

L=limx1nxnx-1-xn-1ex-esinπxPutx=1+hsothatasx1,h0.ThereforeL=limh0h.n1+hn-1+hn-1eeh-1sinπhlimh0n.h1+C1  nh+C2  nh2+C3  nh3+...-1+C1  nh+C2  nh2+C3  nh3+...-1πeh2eh-1hsinπhπh=-n2-C2  nπe=-2n2-nn-12πe=n2+n2πe=nn+12πeIfn=100,thenL=-5050πe

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