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Q.

Line joining the centre of path and cylinder is having angular velocity ω and angular acceleration α at the given instant: Match the statements from List I with those in List II and select the correct answer using the code given below the lists.

Question Image
 List-I List-II
(P)Rotational component of kinetic energy of cylinder(1)(Rr)αi^+(Rr)ω2j^
(Q)Kinetic energy of cylinder(2)ω2R(Rr)rj^
(R)Acceleration of centre of cylinder(3)14m(Rr)2ω2
(S)Acceleration of point of contact(4)34m(Rr)2ω2
 PQRS
(A)3412
(B)2413
(C)1234
(D)4123

 

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a

1

b

2

c

3

d

4

answer is A.

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Detailed Solution

Vcm=(Rr)ω  rotational E=14m(Rr)2ω2  (Q) total kinetic energy =12mvcm2+12lcmω2=34m(Rr)2ω2 (R)acm=(Rr)αi^+(Rr)ω2j^

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