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Linear momentum of a body is given by $p = (20 t - 3 t^{2}) kg - m / s .$ Then the force acting on the body at t = 1 sec,is

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6 N

18 N

12 N

14 N

answer is D.

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Detailed Solution

$P = 20 t - 3 t^{2} kg - m / s$

$∴ F = \frac{dp}{dt} = (20 - 6 t) N$

$At t = 1 \sec, F = (20 - 6 \times 1) N = 14 N$

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