Linear momentum of a body of mass 5 kg is given by p→=t22+5i^Ns. Acceleration of the body at t = 5 s is

Force=dpdt=ddtt22+5=tForce at t=5 sec is 5Nacceleration=Fm=55=1 m/s2

Linear momentum of a body of mass 5 kg is given by p→=t22+5i^Ns. Acceleration of the body at t = 5 s is

Force=dpdt=ddtt22+5=tForce at t=5 sec is 5Nacceleration=Fm=55=1 m/s2

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Linear momentum of a body of mass 5 kg is given by $\vec{p} = (\frac{t^{2}}{2} + 5) \hat{i} Ns$ . Acceleration of the body at t = 5 s is

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−1 ms⁻² $\hat{i}$

1 ms⁻² $\hat{i}$

−1 ms⁻² $\hat{j}$

1 ms⁻² $\hat{j}$

answer is B.

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$Force = \frac{dp}{dt} = \frac{d}{dt} (\frac{t^{2}}{2} + 5) = t$

$Force at t = 5 \sec is 5 N$

$acceleration = \frac{F}{m} = \frac{5}{5} = 1 m / s^{2}$

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Linear momentum of a body of mass 5 kg is given by p→=t22+5i^Ns. Acceleration of the body at t = 5 s is

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Linear momentum of a body of mass 5 kg is given by $\vec{p} = (\frac{t^{2}}{2} + 5) \hat{i} Ns$ . Acceleration of the body at t = 5 s is