Lines are drawn parallel to the line $4x-3y+2=0$ at a distance $\frac{3}{5}$ from the origin, then which one of the following points lies on any of these lines?

Equation of line parallel to line $4x-3y+2=0$ is $4x-3y+k=0$………. (1)

$\frac{3}{5}$ = Perpendicular distance from (0,0) to above line (1)

$\frac{3}{5}=\frac{\left|k\right|}{5} k=\pm 3$

$4x-3y+3=0 4x-3y-3=0$

$\left(\frac{{\displaystyle -1}}{{\displaystyle 4}},\frac{{\displaystyle 2}}{{\displaystyle 3}}\right)$ is lies on line $4x-3y+3=0$