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Q.

LiNO3Li2O+X+Y NaNO3NaNO2+Y

The magnetic nature of X and Y respectively

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a

Para, para

b

Para, dia

c

dia, para

d

dia, dia

answer is A.

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Detailed Solution

4LiNO32Li2O+4NO2X+O2Y 2NaNO32NaNO2+O2

 number of electronsnumber of valency electronsnumbers of unpaired electronsMaganetic proportities
X=NO223171Para Maganetic
Y=O216122para magnetic

O2: is paramagnetic due to presence of 2 unpaired electrons
MOEC of O2
 

large sigma _{1{s^2}}^*;sigma _{1{s^2}}^*;{sigma _{2{s^2}}};sigma _{2{s^2}}^*;sigma _{2{p^2}}^2;begin{array}{*{20}{c}} {{pi _{2{p_x}^2}}}&{pi _{2{p_x}^1}^*} \ {{pi _{2{p_y}^2}}}&{pi _{2{p_y}^1}^*} end{array}
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