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Q.

liquid A and B form ideal solution for all the compositions of A and B at 25°C. Two such solutions with 0.25 and 0.50 mole fractions of A have the total vapour pressure of 0.3 and 0.4 bar respectively. What is the vapour pressure of pure liquid B in bar.

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answer is 0.2.

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Detailed Solution

$P_{T} = P_{A}^{0} X_{A} + P_{B}^{0} X_{B}$
$P_{A}^{0} =$ Vapour pressure of Pure A
$P_{B}^{0} =$ Vapour pressure of Pure B
$\begin{array}{l} X_{A} + X_{B} = 1 \\ 0.3 = P_{A}^{0} 0.25 + P_{B}^{0} \times 0.75 \to (1) \\ 0.4 = P_{A}^{0} \times 0.5 + P_{B}^{0} \times 0.5 \to (2) \end{array}$
(or)
$0.8 = P_{A}^{0} + P_{B}^{0} \to (3)$
Equation (1) and Equation (3) Compare
$P_{A}^{0} = 0.6 bar P_{B}^{0} = 0.2 bar$

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